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Portable Network Graphic  |  1993-02-04  |  2KB  |  512x342  |  1-bit (2 colors)
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OCR: b. Find the distance between the satellite and the tracking station at 12:03 p.m. Solution: Computing angle [ gives 6 = 3 min 120 min 360º = 90 By the law of cosines, x2 = (6400)2 + (8000) - 2(6400)(8000) cos 9º = (40.96 +64 - 101.14) x 106 km2 = 3.82 x106 km2 x =1.96 x 103 = 2.0 x103 km. We have found that the distance between the satellite and the tracking station is 2000 km (to two significant figures) at 12:03 p.m. (See next card.)